Question

Directions: Write out your legible answers in the space provided. Position vs Time 3456789101112 15 16 17 18 19 1. Referring to the graph above, find the displacement and distance from t 2 sto 8 s 2. Referring to the graph above, find the average velocity and average speed from t- 6s tot 15 s.

Answer 1

From the graph. We can see that at t_1 = 2s, position of particle = x_1 = 2 m And at t_2 = 8s, position of particle = x_2 = 2 m Then, net displacement = Delta x = x_2 - x_1 = 2 m - 2 m = 0 Ans. For distance, we count length of the path of the particle, we can see that particle moves from 2m and reach to the location about 3.5 m (it is just an estimation, please, see the figure.) and again, it reach to the location 2m. So, total distance = 2 (3.5m - 2m) = 3m Ans. At = 6 sec, location of particle = x_1 = 3m At t_2 = 15s, location of particle x_2 = 2m Average velocity is defined as v^- = x_2 - x_1/t_2 - t_1 = 2m - 3m/15s - 6s = -1/9 m/s �initial displacement = d_1 = 144 m at the velocity