Item 3 Review Part A A 2.0 m x 4.0 m flat carpet acquires a uniformly...
Item 3 Review PartA A 2.0 m x 4.0 m flat carpet acquires a uniformly distributed charge of -10 C after you and your friends walk across it several times. A 4.0 ug dust particle is suspended in midair just above the center of the carpet. What is the charge on the dust particle? Express your answer with the appropriate units qValue Units Submit Request Answer
Item 3 Review PartA A 2.0 m x 4.0 m flat carpet acquires a uniformly distributed charge of -10 C after you and your friends walk across it several times. A 4.0 ug dust particle is suspended in midair just above the center of the carpet. What is the charge on the dust particle? Express your answer with the appropriate units qValue Units Submit Request Answer
A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several times. A 3.5 μg dust particle is suspended in midair just above the center of the carpet. A) What is the charge on the dust particle?
A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of ?10 ?C after you and your friends walk across it several times. A 3.5 ?g dust particle is suspended in midair just above the center of the carpet. Part A What is the charge on the dust particle? Express your answer with the appropriate units.
Review | Constants Periodic Table From a distance of 4.0 m, a bystander listens to a jackhammer breaking concrete. Part A .. MasteringPhysics: HW 6 (Partial) session.masteringphysics.com/myct/itemView?... How far would he need to move from the jackhammer so that its perceived loudness decreases by a factor of 2? Express your answer with the appropriate units. Submitted Answers ANSWER 1: == 1.7 m r = 5.65 m Submit Previous Answers Request Answer ANSWER 2: r = 3.33 m X Incorrect; Try...
Please explain part A B C and D of this problem
Constants A ring-shaped conductor with radius a 2.20 cm has a Part A total positive charge Q-0.129 nC uniformly distributed around it.(Figure 1) What is the magnitude of the electric field at point P, which is on the positive x-axis at z = 44.0 cm ? You may want to review (Pages 699- 704) Figure < 1of1 > N/C Submit Previous Answers Request Answer ds X Incorrect; Try Again;...
Rev The forces in (Figure 1) are acting on a 3.0 kg object. Part A What is az, the 2-component of the object's acceleration? Express your answer with the appropriate units. HA ? . X.10 Figure 1 of 1 m Value 82 Submit Previous Answers Request Answer 3.0 N * Incorrect; Try Again; 4 attempts remaining 2.0 N 4.0 N 3.0 N Provide Feedback
Item 1 < 1 of 3 > Review Part A The composite beam is made of 6061-T6 aluminum (A) and C83400 red brass (B). If the height h= 40 mm, determine the maximum moment that can be applied to the beam if the allowable bending stress for the aluminum is (o allow = 122 MPa and for the brass (allowbr = 33 MPa. (Figure 1) Express your answer with the appropriate units. ? CH HÅR M = 4982.713 O a...
Review I Constants Periodic Table Part A What does the top pressure gauge in (Figure 1) read? Express your answer using two significant figures. Figure く 1of1 P2-190 kPa Submit Previous Answers Request Answer 200 kPa 3.0 m/s X Incorrect; Try Again; 5 attempts remaining 2.0 m/s 10 m Oil Provide Feedback
A uniformly charged disk has radius 2.50 cm and carries a total
charge of 2.0×10−12 C .
What is the percent difference between the electric fields
produced by the finite disk and by a point charge with the same
charge at x = 20.0 cm?For this question I got that,
E(disk)=.44N/C and that E(point)= .45N/C.
Which gave me a percent error of 2% when I calculated it using
E(point)-E(disk)/E(point).
I don't understand why this is wrong.
Any help with work...