Calculate the quantity of heat energy, in Joules, that is absorbed when a gold (.128J/goC) ring with a mass of 12.68 is warmed from 23.2 oC to 58.1 oC.
Report your answer, in J, using the correct number of significant figures. Do not enter units and do not use scientific notation.

Calculate the quantity of heat energy, in Joules, that is absorbed when a gold (.128J/goC) ring...
Question 15 2 Points How much energy is required to heat 44.72 g of H2O from 10.00 oC to 37.50 oC? (Heat capacity of liquid H2O = 75.37 J mol-1 K-1) (type in the numeric value in Joules - give your answer to 4 significant figures, do not include the units in your answer only the number, do not use scientific notation, do not include comma's) BLANK-1 BLANK-1
An aluminum kettle (Sp. ht of Al = 0.897 J/goC) weighs 1.05 kg. How much heat (in J) is required to increase the temperature of this kettle from 23.0 °C to 99.0 °C? (Report answer in scientific notation with three significant figures)
Use the following experimental data to solve the questions below: mass of water = 98.731 g mass of goldfish before heating = 25.987 g specific heat of water = 4.184 J/g ⁰C mass of goldfish after heating = 25.761 g initial temperature of water = 21.31 ⁰C final temperature of water = 26.77 ⁰C A)Calculate the energy of the burning gold fish reaction (in Joules). Do not include units in your answer. Do not convert to scientific notation. No credit...
A pure gold ring (c = 0.128 J/g°C) and pure silver ring (c = 0.235 J/g°C) have a total mass of 16.892 g . The two rings are heated to 66.901 oC and dropped into a 13.918 mL of water at 21.9 oC. When equilibrium is reached, the temperature of the water is 24.2 oC. What is the mass of gold ring? (Assume a density of 0.998 g/mL for water.) Enter your answer numerically, in terms of grams and to...
A pure gold ring (c = 0.128 J/g°C) and pure silver ring (c = 0.235 J/g°C) have a total mass of 16.884 g . The two rings are heated to 66.895 oC and dropped into a 13.909 mL of water at 21.9 oC. When equilibrium is reached, the temperature of the water is 24.2 oC. What is the mass of gold ring? (Assume a density of 0.998 g/mL for water.) Enter your answer numerically, in terms of grams and to...
Initial Final Mass of Marshmallow (g) 7.1g 6.3g Temperature (oC) 29.1 oC 32.2 oC 1. Calculate the number of Joules released per gram of marshmallow burned. Show all work. Do this as follows: Find the T of water = Tfinal- Tinitial T of water = 3.1oC b. Find the Joules absorbed by the water using the formula below. Show all work. Joules = (10mL water) x (1.00g)/ mL x (3.1oC) x (4.184 joules)/goC The density of water is 1.00 g/mL, and...
Calculate the quantity of heat absorbed by 12 g of water that warms from 30°C to 82 °C Express your answer to two significant figures and include the appropriate units. J are required to heat 283 g of water from 28 °C to 88 °C? The specific heat of water is 4.184 J/ How many (g°C)
Be sure to answer all parts. Calculate the nuclear binding energy (in joules) and the nuclear binding energy per nucleon of: 147 Sm 62 (146.914907 amu) (Round each final answer to 4 significant figures.) Enter your answers in scientific notation. ____________J ___________J/nucleon
A 66.52-g sample of water is heated from 71.33 °C to 80.96 °C. Calculate the energy absorbed by the water in joules. The specific heat of water is 4.20 J/g" in this temperature range. Do not type the units with your answer and use standard notation (not scientific). Type your answer.
Using the Rydberg equation, calculate the energy in joules, J, of the emission line when electrons drop from n2 = 4 to n1= 2 in the hydrogen atom. Hint: Answer includes 3 significant figures, use the format X.XXEX for scientific notation. Relevant constants: h = 6.626 x 10-34 J·s, c = 3.00 x 108 m·s-1, and RH = 1.097 x 107 m-1. Alright I tried to plug in I am getting 1.36x10^-18 what am I doing wrong? is this right...