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Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with 0.15M HCl. Note the following three items on
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Answer #1

Given Molarity of NH3 = 0.125 M Volume of NH3 = 100.00 ml = 0.1000 L We know, Moles = Molarity (M) x Volume (V in L) Molarity

4. pH at equivalent point Moles NH3 = 0.125 * 0.100 mol = 0.01250 mol Molarity of HCI= 0.150 M Given Ka= 1.8* 10^-5 we know p

volume of HCl =0.1 L = 100 ml

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