Question

Bob works in an office of 100 people. He received a score of 4 on his evaluation. The mean (average) score for everyone in the office is 3, and standard deviation is 1.58. What is his standardized score (z-score)?

69.5%

95%

99.87%

There is not enough information to answer this question

Answer 1

Solution: Standardized score (z-score) can be find using formula

$Z=\frac{X-\mu }{\sigma }$

Where X is score, $\mu$ is population mean and $\sigma$ is standard deviation.

Given that

X=4, $\mu =3$ and $\sigma =1.58$

Then,

$Z=\frac{4-3}{1.58}=0.6329$

i.e 63.29 %

Hence, standardized score (z-score) is 63.29%