equilibnum M27 Calculate the hydrogen ion concentration of a solution that is 0.05 M in potassium...

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Answer 1

Answer #1

Ka1 = 1.12 x 10^-3

Ka2 = 3.90 x 10^-6

pKa2 = 5.409

concentration of KHP = 0.05 M

concentration of K2P = 0.15 M

pH = pKa2 + log [salt / acid]

= 5.4 + log [K2P / KHP]

= 5.4 + log [0.15 / 0.05]

pH = 5.89

[H+] = 1.30 x 10^-6 M

hydrogen ion concentration = 1.30 x 10^-6 M

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Answer 2

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