Question

6 The decomposition of ozone in the upper atmosphere is catalyzed by NO. The overall reaction and rate law are: rate k[O][NO] Os(g)+O(g)+20;(g); Write a possible mechanism that is consistent with rate law and identify an intermediate in the reaction. 7. A possible mechanism for the iodide ion catalyzed decomposition of hydrogen peroxide in aqueous solution is: -slow H2O:(aq) +I(aq)H;O(1) + 0I°(aq) -fast H20:(aq) +Or(aq)H:O()) +02(g)+l'(aq) What is: iv) the catalyst? iv) the intermediate ii) the rate law i) the overall reaction 8. Poly(tetrafluoroethylene) (Teflon) decomposes when heated above 500 C. Rate constants are 2,60 x 10s at 530C and 9.45 x 103 s at 620 C. C) what is the a) what is the rate law? half-life of this reaction at 580 C b) what is rhe activation energy E. in kJ/mol? 9. Consider the reaction: 2 NO2 (8) If an equilibrium mixture was found to have [NO2] 0.0125M and [N204] 0.0337 M, what is N204 (8) Kc for the reaction 10. The equilibrium constant, Ke, for the reaction: 2 co (g) C(s)+CO2 (8) is 0.113 at 1100 K. What is the concentration of CO in a mixture at equilibrium if the CO: concentration is 0.035 M? 11. If K 7.5x 10-9 at 1000 K for the reaction: 2 NO(g) N2(@)+O2(@) (a) What is Kp at 1000 K for the reaction? (b) What is Ke for the reaction NO(g) 2N2(g)+ O2(8)

Answer 1

Uz to 20₂ ratek [ Og] [NOJ pornible mechanisms O₂ + NO Norto O2 + NO2 - Slow - fast No toz all son 03t0 202 so rare depends on slow step = K[0₂ILNOJ & rate law is Intermediate en NO2. H2O2 + 2 H2O + 08- H2O2 + or -> H2O +0, +7 - - fast - Slow i overall xxy & H202 > 2H₂0 to the ii) the rate law rate law is written from blowest step sol ote = k [H202] [9-J intermedien the spenny which in geautent nor in product but between the reaction, which is i neither in comes in on polyfetraflarethylene)

238013 8-314 -238613 X1.9 31 813 X 803 en ka 2.6x104 = .089 eles (ko|26")). eloon K3 = 8.676x2.6 X104 Si = 2.09 x 1635 constant at 580°C in 20910 35-11 so nate

ů 0.698 0.69 = 331,5 Second 20092163 2,09 100

Q9 Q NO Z [NO₂] = 0.0125m Ne Oy [N2O4] = 0.0337M 0.0337 215.68 Kee (N2Oy] [NO] (0.012872 (s) + cop (g) 200 g) Kez 0.113 [Coul = 0.035 llo [co] =?? TUYOTT

[C] 21, conc. of as 'kc a [coja In ter [CO] 0.113 : tcog2 1 x 0.035 solid in taben to be a [coge 0-110x0035 6.0628 M