Question

A mixture of hydrogen and oxygen gases, in a 9.90 L Mask at 66°C, contains 0.586 grams of hydrogen and 4.94 grams of oxygen.
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Answer #1

1)

Molar mass of O2 = 32 g/mol

mass(O2)= 4.94 g

use:

number of mol of O2,

n = mass of O2/molar mass of O2

=(4.94 g)/(32 g/mol)

= 0.1544 mol

Given:

V = 9.9 L

n = 0.1544 mol

T = 66.0 oC

= (66.0+273) K

= 339 K

use:

P * V = n*R*T

P * 9.9 L = 0.1544 mol* 0.08206 atm.L/mol.K * 339 K

P = 0.4339 atm

Answer: 0.434 atm

2)

1st find the partial pressure of H2

Molar mass of H2 = 2.016 g/mol

mass(H2)= 0.586 g

use:

number of mol of H2,

n = mass of H2/molar mass of H2

=(0.586 g)/(2.016 g/mol)

= 0.2907 mol

Given:

V = 9.9 L

n = 0.2907 mol

T = 66.0 oC

= (66.0+273) K

= 339 K

use:

P * V = n*R*T

P * 9.9 L = 0.2907 mol* 0.08206 atm.L/mol.K * 339 K

P = 0.817 atm

Now use:

Total pressure = p(O2) + p(He)

= 0.434 atm + 0.817 atm

= 1.25 atm

Answer: 1.25 atm

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