Question

Question 10 Consider the balanced equation representing the reaction of solid copper and aqueous silver nitrate: Cu (s) + 2 AgNO3 → 2 Ag (s) + Cu(NO3)2 What mass of solid copper is required to completely react with 16.6 mL of 0.67 M silver nitrate? Calculate the mass in grams, and report your answer to 2 significant figures.

Answer 1

Number of moles of AgNO3 = molarity * volume of solution in L

Number of moles of AgNO3 = 0.67 * 0.0166 = 0.0111 mole

From the balanced equation we can say that

2 mole of AgNO3 requires 1 mole of Cu so

0.0111 mole of AgNO3 will require

= 0.0111 mole of AgNO3 *(1 mole of Cu / 2 mole of AgNO3)

= 0.00555 mole of Cu

mass of 1 mole of Cu = 63.546 g so

the mass of 0.00555 mole of Cu = 0.35 g

Therefore, the mass of Cu required would be 0.35 g