Question

How many mL of 0.0946 M NaOH are needed to neutralize 25.0mL of 0.0750 M sulfuric acid?

Answer 1

2 Naon & H₂SO4 → Na₂SO4 + 2H₂O moles of H₂ soya molarity & volume = 0.0750 M*(85X10-3L)=1.875x10 201 Now, moles of Nooh needed = ax moles of H₂SO4 -2x610875x10-3)mol = 3.75*10 MOI NJOH moles we know, molarity - anowe, molarity. Tolumelin L) at volume : 3.75X10 mol = 0.0396L 0.0946 MI & volume = 39.6 mL)