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Focus on Concepts, Question 03 A positive charge (q = +6.0 μC) starts from point A in a constant electric field and accelerates to point B. The work done by the electric force is WAB = +5.8 x 10-3 J. Determine the potential difference Vs - VA between the two points. Be sure to include the proper algebraic sign. VB-VA Number Units the tolerance is +/-5% the tolerance is +/-5%

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The work done by the electric force is The potenti al difference is AVWA 5.8x10-3 AB . = 967 V 76.0x10-6

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