Question

hi, my name Devin, i have an online class and this huge question is on my hw. i already tried my first attempt and i only have one more. can i get some help double-checking my work? and yes its

Calculate the pH corresponding to each of the hydrogen ion concentrations given below, and indicate whether each solution is acidic or basic.(a) [H⁺ ] = 3.94 10^-5M

(b) [H⁺ ] = 9.55 10^-8M
(c) [H⁺ ] = 2.12 10^-10M
(d) [H⁺ ] = 1.74 10^-7 M

(e) [OH ⁻ ] = 3.93 10^-2M
(f) [OH ⁻ ] = 6.74 10^-4M
(g) [OH ⁻ ] = 3.13 10^-5M
(h) [OH ⁻ ] = 6.68 10^-3M
(i) pOH = 4.27
(j) pOH = 8.98
(k) pOH = 1.78
(l) pOH = 11.8

(m) 1.09 10^-3M HNO₃
(n) 0.000199 M HClO₄
(o) 4.89 10^-5M HCl
(p) 0.00105 M HBr

Answer 1

pH <7, acidic.. pH7 7 basic.in pH = 7; neatral We can find pH by usung the formula $H log [H]* where it & logan ithen to the base 10 Cent concentsation of Chrions also PH+ POH-. 14. also pOH = -log [oH]: -) 14- pot = pH. I Now, a). [H+] = 3.94 xro u :: pH = -log (3.94x1025) Dog Cab) = ioga + logo =) - [ log (3-44) + log Cros) logan - meoga - - Ilog (3.94) + 5log to]: log 10 = 109, 010-1. log 394 - 0.595 pH <7. ..:-) - [ 0.595 + 5x1) = 4.405 acidic b). [4+79.55*10* logquss pH = -log (9.85x108) un log 9.55+ Blog to] in similarmay =) - (0.98 – 8) = 7.02 27, neutral. Cl. [+) Zila *10-COM. pets - Cog C2:42 8106M.) 2 = log2:12 -10 logeo-) . . 2-t2- 70.326-10) - 19.644; basic (d). Catt: 1.74x107 phe -log (179X107) -[log1174 = 7cog10] coglugga .2405 (0.0405- 7] - 6.75;" acidic - OD-326 e). [OH) - 3.93ť 10% pole-log [OH poct= -log C3-93x102), 2[ log3.93 - Plog lo] 10:594-2) = 1.406 = pott. pH & pot = 14 , pH 14-1.606 - 12.594; basic A) (OH) = 6.74x100 M pOH = -log (6. 74x604) « [logs. 74 - 4 Cogeo] =) - (0.828-47 3. 171 phta 14-poh. 14-3-171 = 10.828, basic.

*). 4.89x10MHCH Hl, skong and dissociater completely so (H) + 4.898105 Cel? =4.89x10m here to log [att - log ( 4.89x10%) - ( cog 4.89 - 5log 10] (0.689-5) = 4.31 acidic. p). 0.00105 HBr = 1.05010 MHBR. AB, Strong and; dissociate completely. so (BrJ. & 605 x 10 CHit- 1.05X1034. pH- - Lag [427 - (lop (1050) [tog 1.05 - 3 lojin) -(0:021-3) 2.97 , acidic. gl. [of]- 3.13 X 10M. potte – log [3. 13x10 5M] : [tag 1.13 - siog 107 -0.495-51: 4.504. - pte 14-.poh 14 - 6.504 = 9.495 basic H. COHJ 668x1534 pote - log (6.68x103] - - (log 6.68 - 3 log10]. => -0.824 4 37- 2.175. pit-14-port. 14-2.175 = 11.824 basic 1) POH = 4.27 pH + po H= 1, pH = 1 - РОН 14-427. 9.73; bàsic i pol - 8.98 pH-14-poh 14-2.98 = 5.00 acidic Dote 11.8 PH: 14- pot = 14-11.8 - 2.2 acidic.. 2. pol. 1-78. pt. 14-polt = 14-1.78 12.22 ; basic (m) 1.09x103M HNO3 Nitric acid CHNO) is a strong acid, so it mostly digsociates completely in staition. also it is monopestic as it provides Imole Hydrogen ion per mole of acid, the concentration of [H7 conc. of nitric guid. & Chit = 1:09xios; . pH log[et] - [ log C1-09x109)] - [ Coll.og) - Flog.co] - [ 0.037-37 = 2.96, acidic. all 4 acids in the questions (HNO3, HCl, HCl, HBP). оке мочора, офіс ома Skodatio same trend go (h) 1 0.000193 - 199X164 s.p. -Log L-99x10 > flog 1.996-4c0g103... 10. 2988 - 47 = 3.70 & audic