Answer:
Given that:
Let X denote the number of boys in a randomly selected three-child family. Assuming that boys and girls are equally likely, construct the probability distribution of X?
Below is probability distribution of X:
P(X=0)=P(All three are girls) = 
P(X=0) =1/8
P(X=0) = 0.125
P(X=1) =
3C1
P(X=1) =3/8
P(X=1) = 0.375
P(X=2) = 3C2
P(X=2) = 3/8
P(X=2) = 0.375
P(X=3) =
P(X=3) = 1/8
P(X=3) = 0.125
3. Let X denote the number of boys in a randomly selected three-child family. Assuming that...
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48. Determine the probability of having 3 girls in a 3-child family. (Assume equally likely outcomes.)
> That is
GGG (0 boys)
GGB, BGG, GBG, (1 boy means 3/8)
GBB, BBG, BGB, (2 boys means 3/8)
BBB (3 boys means 1/8)
Murphy Thu, Apr 22, 2021 6:47 PM