Question

1.What will be the reaction rate at 0.0550 mM [G6P]? (2)

2. If the enzyme concentration is unchanged, at what G6P concentration will the reaction rate equal 1.650 mM/s? (2)

3. What PGI concentration is required to give a reaction rate of 4.000 mM/s at 0.0300 mM [G6P]? (2)

Calculated Vmax=1.440mM/s Km=0.0330 mM

The enzyme phosphoglucose isomerase (PGI) catalyzes the following reaction in glycolysis сH,ОРО,2- Phosphoglucose 2-03POH2C сH,он о. н Н н isomerase но он н Н Н он он но но Н Н он Glucose 6-phosphate Fructose 6-phosphate Kinetics experiments were performed on PGI. Enzyme activity (initial velocity, V) was measured at varying concentrations of Glucose-6-phosphate (G6P). The enzyme concentration used in all experiments was 1.5 HM. The data are shown below [G6P] (mM) Vo (mM/s) 0.01 00 0.360 0.0200 0.600 0.0400 0.900 0.0800 1.200 0.160 1.440

Answer 1

Answer ta problem Michaeli- Menten saadin fa wzym aa 14 Kn T61. KM=Michaeli Manten tonstat I67.= 4miHal Aubstrat Ceuetntahen VIman =[Ex K 146P3 0.055 mM = I. Vm an 1-440 mM/S Kn 0 033 I-44D 1 0.033x 0.055 440 = 0.9 mMS It 0-6 2. 1G6P-18,-2 V 1.650 mM|s VWAX 1+ 440 N1.650 0-033/19 1.440 1650t 1.650x 0.D33 1650 0.033 O.21 Is]. -0.25 mM 259 MM -Ls1

3. Vmax ON440 mMs h x 5 MM 3 -440x10 MM5 960 54 4 MAIS P&1=1E.=? 0 .03 mM b1 Vne-KxTET. V I+ l/IS7 960x 1E7 4 O.033 O.03 14 9 60x 1E1, = 4x 2-1 84/460 TE1 бy 8-75x103 m M E70 875 MM E1