7. The curve for the titration of 25.0 mL of 0.100 M CsHsN(aq), pyridine, with 0.100...

Question

Question

7. The curve for the titration of 25.0 mL of 0.100 M CsHsN(aq), pyridine, with 0.100 M HCl(aq) is given below. Estimate the p

science chemistry

Answer 1

Answer #1

Answer

d) 8.8

Explanation

At half equivalence point

pH = pKa

equivalence point = 24

half equivalence point = 12

at half equivalence point pH = 5.1

pKa of C5H5NH⁺ = 5.1

pKb = 14 - pKa

pKb of C5H5N = 14 - 5.1 = 8.9

Answer 2

Similar Homework Help Questions

Sketch a titration curve for the titration of 25.0 mL of 0.100 M NaOH with 0.0500...

Sketch a titration curve for the titration of 25.0 mL of 0.100 M NaOH with 0.0500 M HCl. Locate the equivalence point for each of the titration curves in problem 1.
Calculate the pH for each of the cases in the titration of 25.0 mL of 0.100...

Calculate the pH for each of the cases in the titration of 25.0 mL of 0.100 M pyridine, C5H5N(aq) with 0.100 M HBr(aq) . A. before addition of any HBr B. after addition of 12.5 mL of HBr C. after addition of 23.0 mL of HBr D. after addition of 25.0 mL of HBr E. after addition of 31.0 mL of HBr
Calculate the pH for each of the following cases in the titration of 25.0 mL of...

Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.160 M pyridine, CsHsN(aq) with 0.160 M HBr(aq): Number (a) before addition of any HBr Number (b) after addition of 12.5 mL of HBr Number (c) after addition of 24.0 mL of HBr Number (d) after addition of 25.0 mL of HBr Number (e) after addition of 29.0 mL of HBrIL

Calculate the pH for each of the following cases in the titration of 25.0 mL of...

Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.120 M pyridine, CsHsN(aq) with 0.120 M HBr(aq): Number (a) before addition of any HBr Number (b) after addition of 12.5 mL of HBr Number (c) after addition of 22.0 mL of HBr Number (d) after addition of 25.0 mL of HBr Number (e) after addition of 32.0 mL of HBr
calculate the pH of the titration mixture when 39 mL of 0.100 M HCl (aq) is...

calculate the pH of the titration mixture when 39 mL of 0.100 M HCl (aq) is added to 20 mL of 0.100 M Ba (OH)2 (aq)?
A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 25.0 mL of 0.10 M...

A 10.0 mL sample of 0.25 M NaOH(aq) is titrated with 25.0 mL of 0.10 M HCl(aq) (adding HCl to NaOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture. 1) After adding the HCl solution, the mixture is [ Select ] ["before", "at", "after"] the equivalence point on the titration curve. 2) The...

Two 25.0 mL samples of one 0.100 M HCl and the other 0.100 M HF were...

Two 25.0 mL samples of one 0.100 M HCl and the other 0.100 M HF were titrated with 0.200 M KOH answer each of the following questions regarding these two titrations Two 25.0 mL samples, one 0.100 M HCl and the other 0.100 M HF, were titrated with 0.200 M KOH. Answer each of the following questions regarding these two titrations You may want to reference (Pages 755 - 769) Section 17.4 while completing this problem. Part A What is...
Attempt 1 Calculate the pH for each of the cases in the titration of 25.0 mL...

Attempt 1 Calculate the pH for each of the cases in the titration of 25.0 mL of 0.100 M pyridine, C5H5N(aq) with 0.100 M HBr(aq) . A. before addition of any HBr 9.11 B. after addition of 12.5 mL of HBr 8.77 C. after addition of 14.0 mL of HBr 8.88 D. after addition of 25.0 mL of HBr 2.005 E. after addition of 32.0 mL of HBr 1
Calculate the pH for each case in the titration of 50.0 mL of 0.100 M HCIO(aq)...

Calculate the pH for each case in the titration of 50.0 mL of 0.100 M HCIO(aq) with 0.100 M KOH(aq). Use the ionization constant for HCIO. What is the pH before addition of any KOH? pH = What is the pH after addition of 25.0 mL KOH? pH = What is the pH after addition of 30.0 mL KOH? pH = What is the pH after addition of 50.0 mL KOH? pH = What is the pH after addition of...

Consider the titration of a 25.0 mL sample of 0.100 M HCl with 0.200 M KOH....

Consider the titration of a 25.0 mL sample of 0.100 M HCl with 0.200 M KOH. The volume of equivalence is 12.50 mL. (Remember to report pH values with two places past the decimal point.) A)What is the pH of the sample before any KOH is added? B)What is the pH after 9.00 mL of KOH have been added? C)What is the pH at the equivalence volume? D)What is the pH after the addition of 14.0 mL of KOH?