Question

1. A solid sphere with a diameter of 120 cm has a total positive charge of 200 p/C uniformly distributed throughout its volume. (a) Calculate the intensity of the electric ficld at the center of the sphere. (b) Calculate the clectric field at a distance 10 em from the center of the sphere. (c) Calculate the electric field at a distance 100 em from the center of the sphere. (d) Where is the maximum field intensity reached? (e) Is the sphere made of insulating or conductive material?

Please Show steps, Thanks in advance :)

Answer 1

P = q/4/3 pi r^3 = 3 times 200/4pi(1.20)^3 = 27.631 mu_c/m^3 ea = q_enclosed/e_90 e = pr/3e e = (27.631 times 10^-6) (0)/3(8.854 times 10^-12) = 0 n/c f = (27.631 times 10^-6)(0.10)/3 times (8.854 times 10^-12) = 1.04 times 10^5 n/c e_max = q/4pi e_o r^2 = 200 times 10^-6/4pi(8.854 times 10^-12)(1.20)^2 = 1.25 times 10^6 n/c e_100 cm = (27.631 times 10^-6)(1.0)/318.854 times 10^-12 = 1.04 times 10^6 n/c sphere is mode of conductive material change is uniformly distributed

Maximum at the surface of the sphere , at 120 cm .