Question

Please show work to explain!

QUESTION1 1 points Save Two positively charged particles are placed 3 cm from one another on the x axis (see image). Particle 2 has twice the charge of Particle 1 (q2-2q,). The force on particle 2 is 4 N in the +x direction. What is the magnitude of the force on particle 2? 04 N 00N O2 N O The exact charge of the particles must be known to solve this problem.

Answer 1

Let

Let q_1 = q and q_2 = 2 q Given is: Distance between the charge = 3cm or 0.03m Force experienced by charge 2 is F = 4N Now The Force between the two charged particles is given by F = K q_1 q_2 /r^2 Therefore the force exerted by charge 1 on to charge 2 is exactly the same in magnitude by the force exerted by charge 2 on to the charge 1 but in opposite direction. Thus the magnitude of the force on particle 2 is 4N Hence option - 1 is correct answer. Similar polarity charges experience the repulsive force therefore the force on particle 1 due to the particle 2 is in -x direction Hence Option - 4 is correct answer.
and   

Given is:-

Distance between the charge = 3cm or 0.03m

Force experienced by charge 2 is F = 4N

Now

The Force between the two charged particles is given by

Therefore the force exerted by charge 1 on to charge 2 is exactly the same in magnitude by the force exerted by charge 2 on to the charge 1 but in opposite direction.

Part-a

Thus the magnitude of the force on particle 2 is

Hence option - 1 is correct answer.

Part-b

Similar polarity charges experience the repulsive force therefore the force on particle 1 due to the particle 2 is in -x direction

Hence

Option - 4 is correct answer.