calculate the ph of 0.25 M HNO2 (Ka= 4.0 * 10^-5)

Question

Question

science chemistry

Answer 1

Answer #1

kao 4x10-5 0.25 m ka= [rit] [A [HA ] PH = -log [mt] HNO, & HNO2 ka [ht] [ Nor] = 4X105 [HNO] HNOLZ H+ + Nor Initial 0.25M 0 0

Answer 2

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