Question

AS is negative for the reaction O CH3OH(1) + CH3OH(g) OKBr(aq) + K+ (aq) + Br(aq) O C6H12O6(s) + 6 C(s) + 6 H2(g) + 3 02 (g) O 2 NH3(g) + N2(g) + 3 H2(g) Mg(NO3)2 (aq) + 2 NaOH(aq) → Mg(OH)2 (s) + 2 NaNO3(aq) Submit Request Answer

Answer 1

AS = Change in entropy - entropy directly depend upon disordernes of system. more the ordered system consist less en troby. @ cnz ohle) cnz on (0) AS 2 S Product - S reachent liquid phase comparatively more entropy AS = tive more ordered than gas pheuse less entroby - KBr (99) Ka (a + Bro (92) On going from Reactant to product product have more number of ions or atoms in qq. phone than reactant. so kBrass - less Ktag) + Boaz, nit L-unit Chopy entropy more ions moreentropy 9 ion © ll So As = tive gas molecules have high entroby. COM1206 (5) > 6 C(s) +61265) +30219) Solid lessentoob gas more entropy So as ative 2 N13kg) = N26) +377 (0) w g mole (9) 4 mole gar- less entropy more entroby So As =tive @

→ Molonas, + QNGNO3 (92) Mg(NO3)2 (aq) + 2NaOH al) Į mole (99) a moleaq. 3 mole aq have more entropy Imole solid & mole caq Imole solid have less +2moleca entropy So AS z-ive Solid have less so in option entroby than aq. ® As - negative