Question

(15 pts) Consider the position-time graph shown in P 1.20. Explain why your choice is correct. a. Over what time interval is the objects average velocity positive? b. Over what time interval is the objects average velocity negative? c. Over what time interval is the objects average velocity zero?
I Write a short description of the motion of a real object for which FIGURE EX1.20 would be a realistic position-versus-time graph. x (mi) 20 0 1 2 3 45 FIGURE EX1.20-20
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Answer #1

Please note that from distance-time curve we can find average velocity over specific time by checking the slope of that graph.
If the curve is leaning towards positive time axis then slope is positive and hence velocity is positive.
If the curve is leaning away from positive time axis and towards negative time axis, then slope is negative and hence velocity is negative.

If the curve is along time axis, then slope is Zero and hence velocity is zero.

a) So, for t =3s to t =5s , we see that slope is positive hence, average velocity is positive in this region.

b) Similarly. for t=1s to t=2s the velocity is negative.

c) The velocity is zero in two intervals that is t=0s to t=1s and then t=2s to t=3s

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