Question

Show that Brewster's Law (where the incident angle $\Theta$i = $\Theta$p ) and Snell's Law together imply that $\Theta$p +$\Theta$2 = 90 degrees.

Answer 1

A/c to Brewster�s law mu = tan theta_p mu = sin theta_p/cos theta_p (1) A/c to snell�s law mu = sin theta_i/sin theta_r (2) given that theta_i = theta_p put in (2) mu = sin theta_p/sin theta_r (3) equale (1) & (3) sin theta_r = cos theta_p cos (90 degree - theta_r) = cos theta_p 90 degree - theta_r = theta_p theta_p + theta_r = 90 degree \r\n we know that reflected angle is equal to angle of incidence given that theta_i = theta_p At so, reflected and refracted becoms are always at right angle to each other therefore theta_p + 90 degree + theta_r = 180 degree theta_p + theta_r = 90 degree (theta_r is angle of refraction)