Question

If 23g of C4H10 were combusted with 37g of Oxygen, one reagent is limiting? How much of the non-limiting reagent will be left over after the reaction is completed?

Answer 1

When C4H10 were combusted with oxygen then the reaction proceeds as follows 2C4H10 + 1302 = 8C02 + 10H2O MW 58.12 MW 36 2 mole ofC4H10 react with 13 moles of O2 So, (2 x 58.2) g of C4H10 react with (13 x 320g of O2 or 116.4 g of C4H10 react with 416 g of O2 or, 416 g of O2 react with 116.4 g of C4H10 or, 37 g of O, react with (116.4 x 37)/ 416 g = 10.353 g of C4H10 Therefore, when 23g of C4H10 were combusted with 37g of oxygen; then oxygen is the limiting reagent which is fully consumed after the reaction. So, the non-limiting reagent, C4H10 will be left over after the reaction is completed and the left over amount is =(23 - 10.353) g = 12.647 g of C4H10