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65 mi/h suddenly (13%) Problem 7: On notices a truck 0.15 mi in front of him. That truck is moving in the same direction at v2 31 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δ. The smallest magnitud of acceleration required for the car to avoid a collision is a. During this problem, assuhme the direction of motion of the car is positive direction. Refer to the figure. a one lane road, a person driving a car at vi
| 11% Part (b) Enter an expression for the distance, Ari, traveled by the car in terms of vi, v2 and a.
ー #11% Part (c) Enter an expression for the acceleration of the car, a, in terms of vi, a = v 2-v/Δ1 X Attempts Renaln v2, and Δ. Feedback: is available.
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a ss 11% Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms ofd, vi, and 2. a-(v v2F2d Attempts Remaln Feedback: is available. ム11% Part (i) Calculate the value of a in meters per second squared.
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