Question

(1 point) A length or bone Escompressed to its fracture point by a force of 6600 N. The force required to compress a onger length of the same bone to its fracture point is OA. time dependent B. unabie to te C. smaller than 6600 N. D. larger than 6600 N E. equal to 6500 N (a) e (1 point) (c) e Which one of the graphs in the image above represents the dependence of the twist-angle θ on the length Z of a solid rod of radius r, when the torque causing the twist is the same for all lengths OA. (a) B. (b) C. (C) D. (d) (1 point) The shear modulus or bone is 9 × 109 N/m2, or copper 4 × 1010 Nrm2, and or aluminum 2.5 × 1010 N/m2. For identical pieces same dimensions) of these materials, which one would twist most easily? Rank in order from easiest to most difficult A-Bone, copper, aluminum B. Bone, aluminum, copper C. Aluminum, bone, copper

Answer 1

* Fracture point is represented by the breaking stress which has nothing to do with the length, it is simply Force per unit area hence same force is required to get the fracture point for a longer bone. Option (E) is correct.

* Angle of twist is given by $\theta$ = TL/JG where L is length of rod so clearly there is a linear relation between angle and length hence curve between them should be a straight line. Hence option (C) is correct

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