Question

IReview I Constants Periodic Table The presence of SO2 in the atmosphere and the sulfuric acid that it produces result in the phenomenon of acid rain. Uncontaminated rainwater is naturally acidic and generally has a pH value of about 5.6. The pH of acid rain is about 4 Part A This acidity has affected many lakes in northern Europe, the northern United States, and Canada, reducing fish populations and affecting other parts of the ecological network within the lakes and surrounding forests. If the pH of a 1.00-in. rainfall over 1400 miles2 is 3.20, how many kilograms of sulfuric acid, H2SO4, are present, assuming that it is the only acid contributing to the pH? For sulfuric acid, Kal is very large and Ka2 is 0.012. Express your answer to two significant figures and include the appropriate units. View Available Hint(s) The pH of most natural waters containing living organisms is between 6.5 and 8.5, but freshwater pH values are far below 6.5 in many parts of the continental United States. At pH levels below 4.0, НА all vertebrates, most invertebrates, and many microorganisms are destroyed. More than 300 lakes in New York State contain no fish, and 140 lakes in Ontario, Canada, are devoid of life. The acid rain that appears to have killed the organisms in these lakes originates hundreds of kilometers upwind in the Ohio Valley and Great Lakes regions. Some of these regions are recovering as sulfur emissions from fossil fuel combustion decrease, in part because of the U.S. Clean Air Act of 1990, which required that power plants reduce their sulfur emissions by 80%. Value Units Submit Provide Feedback Next

Answer 1

pH = 3.20 H* )= 10pH = 10-3.30 = 6.3x10+ M ICE table for the ionization of HSO, HSO; - soz I(M): C C(M): -X E(M) C-x + H +* C+ From ICE table, H*] = 30 1 =C+x = 6.3x10*M = x=6.3x10-C Acidionization constant. ridionization constant, K- (30 ]H] THS07] 0.012 = *(C+x) (C-x) (6.3x104-C)(6.3x104) 0.012 = (2C-6.3x104) C = 0.00032 According to the equilibrium table, (HSO; lattion=C = 0.00032 M -------------------------------------- Equation representing the ionization of H,SOR H,504 (aq) —— H* (aq) + HS07 (aq) Since H,SO, is a strong acid, it dissociates completely (HSO:] = [H,80] (H,80,] = [HS0;] = 0.00032 M ----- -- ------ -------- ------ --------- --- Concentraion of H,SO. = 0.00032 M Volume of rain fall = (1.00 in x lamin x(1400 mi?) = 0.0221 mix 4.168x10L 1 mi' = 9.21*100 L 0.00032 mol H SO, Amount of H, SO, = 9.21x100 LX4 98.0 g 1 kg 1 mol H,So. 10 g = 2888256 kg = 2.9x10° kg