Question

Part A The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the reactant, the time interval, and the coefficient of the reactant Consider the following reaction: 2A + 3B 3C + 2D The concentrations of reactant A at three different time intervals are given. Use the following data to determine the average rate of reaction in terms of the disappearance of reactant A between time=0s and time = 20 S. Time (s) 0 20 40 A(M) 0.1200 0.0720 0.0540 Express your answer in molar concentration per second to three significant figures. View Available Hint(s) 190 A A O O ? The rate of reaction = 4.10 4 M.5-1 0 You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Part B

Answer 1

Solution : - Given that :- PART: A 24 +38 --> 30-12D Rate of reaction : 1/2 dA) = 7 / does - t de a dos Given: A) in Time Sec) 0.1200 [B] 0.0720 [B] - SHO 2o Ho tz t del]-[R] dt det = 0.0790 - Oldoo . 20-0 => A) = -0.048 20. 2 -0.0024 M/sec

at Rare of reaction - d[A - W. CA] :-* * -0.004 m/sec 5 +0.0012 12.00x10 3 Misec Rate of Reaction = 12x104m/sec 10.10-3 PART :B 2A+ 3B * 36 tap Race > * 42 - Pate of Apperance of coś 46) at - s 0.0720 - 0.000 C 0.072 0.0036) $ 119.00X163-15

PART :C AB CAD A = 0.400 M B = 0.290 M Rate of reaction - 01060 Mos! Order of A order of B = 2 Rate of law :- Pate ak (4] [B]² 0.060 = K (0.400 M) X(0.940 M3 - 1.78 Ms Rate (1.78 M² 5