Question

Class Practice C152-02 Chapter 16 Practice 2 - Rate Law Consider a chemical reaction between compounds A and B that is first order with respect to A, first order with respect to B. and second order overall. From the information given below, fill in the blanks Initial Rate Initial (A) Initial [B] Experiment (Mrs) (M) (M) 1 4.0 x 100 .20 0.050 2 1 .6 x 102 0.050 3 3.28 10² 0.40 T Consider the following rate data for the reaction below at a particular temperature. 2A +3B - Products Experiment Initial [A] Initial [B] Initial Rate of Loss of A 0.10 M 0.30 M 7.20x10% Me! 0.10 M 0.60 M 1.44x10Mos! 0.20 M 0.90 M 8.64 x10-4M- The reaction is order in A and order in B.

Answer 1

let us consider the rate constant to be k. 1 Rate K [A][B] Given; 4.0x 10-3 = KX 0.2040.050 7 K = unchanged. 0.40 M-1 8-1 = K shall be irrespective of concentration & For experiment za det initial [A] be coa for 16 x 10-22 0.4x 0.050 i la = seco 0.8 =) [ AI four experiment a y 0.81M) experiment 3: det initial [B7 be y 3.2410-1 = 0.980.noxy .y ? (M) =) [B] for experiment 2

A x ß orden Wagit and bart be d order wirgit det reaction ļ dividing . Ratez k[ Aga [ B] P a 7.20x108, klo.1094 [ 0.30] P 1:44 X 10-4. kl 0.10] [ 0.60 : .20x10-5 10.807B 1.4.48 10-u o.fo J °/^ [0.607B or Pos DDS 7.20 Xito = )" iuu OT; þ=1 : $ 211 aiven . Rate = k [0.200d [ 0.907P g.buy 10- 4 k [0:20][0,90] 8.64 x 10-4 7.20 x 10-5 = 1 : 3.20 910.90 0.30 010

ori 12 = 22.3 or 4 = dd pr. 2? gd 8=2] Thus the reaction 1st order in .B. and order in A is and