Question

1.) NaH D₂C D₂C - 2.) Br Dac KO+Bu bulkybose less sulas E s elimination Dracemic SN D₂C piemic I Br KOET D₃C & racemic SW2 Ez elimination BC P₂C i NaN₃ ON
how do you solve for the major deuterium containing products and where it is optically active or racemic.

Answer 1

OH Q. How do you solve for major product & whether it is optically active or Racemic mixture Son: ci Nalt product - Br Sol" We know that this reaction occurs due to cleavage of oH bond & metal reacts with acidic Hydrogen of alcohol to evolve H₂ gan. f fornys correspondino sodium Alkonide 133 DC OH NaH be no + H₂ or DC VONa Now, This alkoxide e fodium alkouide Sodium further reacts with alkyl halide via SN mechan the reaction is known as Wilaw Synthesis reaction & give corresponding ether. DC ONG + Br Do now major product Product is Optically gnactive) im & (8) C ko КоА-Ви Product We know that Potassium tert butonide is a strong base, it proceeds through Elimination &ku mechanism & form alkene corresponding all Due to the more bulky group is. Kot By then less substituted alkene in major product. DC Vf DV optically inactive. major. Optically active

KOE Produt- I Do In this ok?, not a bulky reagent is present Here there is a probality of Proceeding through both mechanism Elimination on and as well substitution mechanum, Here To Products are : 10-Et. "Ç V Inactive- ophically active) Elimination Produit maior Cont r Substituted prod (minor) ol Optically active. - Br NaNz product CD We know that azide B is an very good nucleophile & occurs mainly through SN² mechanism & some case SNI favourable NON₃ CO3 optically incactive)