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5. A negative charge of -5 nC O). What is its ele a pint (1.0m) and a positive charge of +10nC at poinmt (-1.0m 72 chỉ Eie tl 16 = (c) (0,1m) ゲ, I know her . Iust that 내le ott (d) (2m,-1m) 니2 lb = (clx1 o X.tono.С. 2.
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Answer #1

Here we will use the basic method of finding the electric field.I'll show you two methods of finding the direction of electric field .

个 tionc(a) . Eloctric held at Pont (0,0) duuto both change 2, ond 22, - Elechic held at a(oo) dus to chonge 2, 9 Chory al 2 omd Elecihic elat alo,o) dus to chorge 22 9,X log = 02 CI) Ea2= go Me (repulsive) uhich is thenElectric field on th오 pond b (2m, o) due te chong, 2r bj us (U)2 not)b S(-1) +90 a = 12)2 2- This helod have ture componants CI 乒 15-9123CL) NICeng nus Ci 2- IS-9123 C-1 Nns tha electric held at clo,」rn) dua to 22, ,- C2 12)2 again thuis heldl hare tue compmuts along X- apuis 31.26 ) MIc omd alengY Ond aloma yanis Een) then the net elachnc held at cto,m) aleng X-Gus IS. 912.3 (-2) + 3). 426 (-1) = Entc7again nat electore held alcng y-cous net c = (E C. S oot d) di MI di Lath divection held is E,_ 너.SX(-3-t.j | Nle dl ) JI6 2 1623field at dl2m, *1m) due to change 22 d2 2- us then the net ele chic held at Pnntd(2m-1m)」For any doubt please comment and please give an up vote .Thank you

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