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An electron of mass me = 9.11x 10^-31kg and a charge of qe = -1.60 x...

An electron of mass me = 9.11x 10^-31kg and a charge of qe = -1.60 x 10^-19 is released, from rest, in a region of uniform electric field that points to the right with a magnitude of E=3.43 N/C. How long does it take for the electron to reach a speed of 4.49 x 104 m/s? Assume the experiment is performed in a vacuum and that you can ignore the effects of gravity and friction.

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Answer #1

This question is based on the Newton's equation of motion and concept of force exerted on a charge in presence of an electric field. The detailed calculation is as per following:

| 8、Iulian Let, uo go -h elects Foce on electon · du人to electic field.-- ) Tus) accele/ation of election, a = Now, dem Neutonó enn motion rm う亡ーゾm OVE (A.us * 10-Je (3-11* 10-31 ) C1.6米16 )) * (3,y3) -19 Thanks

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