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If 0.252 g of Ni(NO3)2 6H20 reacts with 1.77 mmol of NaSCN and 1.65 mmol of PPH3 in the presence of excess triethyl orthoform

Consider the overall balanced chemical equation:

Ni(NO3)2·6H2O + 2 NaY + 2 PPh3 + 6 HC(OC2H5)3  → [NiY2(PPh3)2] + 2 NaNO3 + 12 C2H5OH + 6 HC(O)OC2H5

where Ph = C6H5 and Y = SCN or NCS (ambidentate ion).

MW of Ni(NO3)2·6H2O = 290.8 g/mol

MW of NaSCN= 81.07 g/mol

MW of PPh3= 262.3 g/mol

MW of [NiY2(PPh3)2] (Y = SCN or NCS) = 699.5 g/mol

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Answer #1

NiNO 6,0 + 2asN 2pphg-6 AClass3 [NY leeh NaNo, 12 Hs Ou 6HClolaGHs +- No of bules ofNiNo62 Mas Molan Mars Q00066515 mal 0-252

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