Solution:-
a)
| Source of variations | Sum of squares | Degree of freedom | Mean Square | F | p-value |
| Factor A | 21 | 3 | 7.0 | 56.54 | 0 |
| Factor B | 23 | 2 | 11.5 | 92.88 | 0 |
| Interaction | 160 | 6 | 26.667 | 215.39 | 0 |
| Error | 52 | 420 | 0.12381 | ||
| Total | 256 | 431 |
b) The p-value for the factor A is almost 0.
Reject null hypothesis, we can conclude that the means are different within factor A.
c) The p-value for the factor B is almost 0.
Reject null hypothesis, we can conclude that the means are different within factor B.
d) The p-value for the factor A and B is almost 0.
Reject null hypothesis, we can conclude that there is interaction between factor A and factor B.
The calculations for a factorial experiment involving four levels of factor A, three levels of factor...
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CH13 Q8
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