Question

Write the formula of the coordination compound tris(bipyridine)iron(II) bromide. Enclose complexes in square brackets, even if there are no counter ions. Do not enclose a ligand in parentheses if it appears only once. Enter water as H2O. If any abbreviations are given in blue below, you must use them in your answer. Enclose abbreviations in parentheses if there are more than one. C30H24CL2FEN6 X

Answer 1

The Name and the structure of the Complexes 1,2, and 3 respectively are given as follows:

1. lithiumtetraoxalatozirconat (IV) = Li4[Zr(C2O4)4]

2. lithiumhexacyanoferrate(III) = Li3[Fe(CN)6]

3. tris(ethylenediamine)platinum(IV)nitrate = [Pt(H2N-CH2-CH2-NH2)3](NO3)4

w [ Zr CC204) 4 ] - 1. The The change of the charge of the lithium ion is Lit = + Oxalate con is coa = -2 10. The complex containing 4 Lithium in and 4 Oxalate con so, the not charge of the lithium & +4 and oxalate is :-8. (os By this, we can conclude the charge of the metal cation zirconium as +4, as follows The name of the positive ( Lithium) in complex is starts from the to Negative ion C complex). 10 The Name of LA [ Zr CC₂04) i lithium tetraorala to zirconate (IX).

2. Lithium hexacyano female en 10 Here, the re is in ci]]) onidation state. • The name indicates 6 cyanide ligands, reach. Cyanide ligand has unt negative charge (-1) (" By using oxidation state of recy and 6 CN we can present conclude the number of lithium ion in the complex. (0) The complex formula is given as free +3 - 3 Lig [Fe(CN)o]

tris (ethylene diamine) platinum (IV) nitrate: os No having unit (tres charge. o ligand (because ethylene dianure has no net charge it is nentral ligand). ben 10 The formula of the compound is given as; SL p (H₂N- co zem-NH) ] }(NO3). t 4 -4 -CH₂-CH рrly I pt CHN-er2-CH2-N2) 3 (NO) con [ para cen),] Nos y