The drawing in #16 of the textbook shows a person looking at a building on top...

Question

Question

science physics

Answer 1

Answer #1

the height of the building in part a

tan theta = y/x

y1 = tan theta x

= tan35 * 85

=59.51 m

the height of the building in part b

tan theta = y/x

y2 = tan theta x

= tan38 * 85

=66.4m

the height of the antenna is

dely =y2- y1 = 66.4 m - 59.51 m = 6.88 m

Answer 2

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