Following is the - complete Answer -&- Explanation: for the given: Question: in....typed format....
Answer:
Hvap = 21.17
kJ/mol
Hvap = 31.71
kJ/mol
Hvap = 18.156
kJ/mol
Explanation:
Following is the complete Explanation: for the above: Answer.
We are given with the following: information:
| compound | chemical formula | Theoritical heat of vaporization;
Hvap |
Boiling point, Tb , Kelvin ( K ) |
| chloromethane | CH3Cl | Hvap
= 21.40 kJ/mol |
Tb = 249.06 K ( Kelvin ) |
| Water | H2O | Hvap
= 40.65 kJ/mol |
Tb = 373.15 K ( Kelvin ) |
| Hydrogen sulfide | H2S | Hvap
= 18.67 kJ/mol |
Tb = 213.6 K ( Kelvin ) |
We know that: according to Trouton's rule: the following:
Calculated:
Hvap = ( 85.0 J / K. mol )
x ( Tb )
-------------------------Equation - 1
Using the given: information: and Equation - 1; we can form the following table: using MS Excel: presented below, in image format....

We know: we can calculate, the percent errors: in the above calculations, for each of the compounds using the following: formula:
i.e.
percent error = { [ calculated
Hvap - Theoritical
Hvap ]
/ ( Theoritical
Hvap) } x 100.0 % --- Equation -
2
Using the above information and Equation - 2: and using MS Excel: we get the following: table: in....image format...

Trouton's rule states that the molar enthalpy of vaporization of a liquid that does not have...
2. A useful generalization known as the Trouton's rule states that, for many non-associated liquids at their normal boiling point, the standard molar entropy of vaporization has a value of about 87 J molK. a) Given that the standard molar enthalpy of vaporization for water is 40.7 kJ mol , calculate the standard molar entropy of vaporization of water. b) Does water obey Trouton's rule? Explain. c) The normal boiling point of CC2F2 is -29.79 °C and AH ap 20.2...