Question

P8. Suppose we place a charge q at the 1:00 position on a clock face, a charge of 2q at the 2:00 position, a charge of 3q at the 3:00 position, and so forth, until a charge of 12q at the 12:00 position. If,-+1.00 μC, and the distance from the center of the clock face to the position of any of the charges at the numbered positions is R 15.0 cm, calculate the electric4 field at the center of the clock face 11q 10 24 34 94 84 74 54 64

Answer 1

The formula to calculate the electric field due to a point charge os given by, EF=KQ/(RxR)

Therefore, we calculate the electric field due to each point charge whose direction is opposite to the charge placed.

In the next step, we calculate the net electric field due to individual electric field vectors who all have an angle 30° between them and find out the net magnitude which comes out to be 33.93x10⁵ N/C in the south east direction. The elaborate steps are given below ⬇️⬇️

lv to 2 -', INDIV İ DVAL ELECTRIC feLDs* に2x16-y NET d2

Y2West ade a magwibu 0 230 6o alon

n2 Reolwbng Aalong