(1)
For Bears,
P = 300 - 2QB (Where QB: Number of seats for Bears game)
2QB = 300 - P
QB = 150 - 0.5P
For Viking,
P = 240 - 2QV (Where QV: Number of seats for Viking game)
2QV = 240 - P
QV = 120 - 0.5P
(a) With single pricing model,
Total demand (Q) = QB + QV = 150 - 0.5P + 120 - 0.5P
Q = 270 - P
P = 270 - Q
Profit (Z) = Revenue - Cost = (P x Q) - (MC x Q) = 270Q - Q2 - 0 [Since MC (Marginal cost) is zero] = 270Q - Q2
The profit-maximization problem is:
Maximize Z = 270Q - Q2
Subject to Q >= 0
(b) Profit is maximized when dZ/dQ = 0 and d2Z/dQ2 < 0.
dZ/dQ = 270 - 2Q = 0
270 = 2Q
Q = 135
P = 270 - 135 = 135
d2Z/dQ2 = d/dQ(270 - 2Q) = -2 < 0, so second order condition is satisfied.
(c) Profit maximizing attendance (Q) is 135 seats.
(d) Profit = (270 x 135) - (135 x 135) = 36,450 - 18,225 = 18,225
(e) From market demand function, when Q = 0, P = 270 (Reservation price and vertical intercept of demand curve).
Consumer surplus = Area between demand curve and market price = (1/2) x (270 - 135) x 135 = 67.5 x 135 = 9,112.5
NOTE: As per Answering Policy, 1st part with multiple sub-parts is answered.
2 Variable Game Pricing Consider that the Minnesota Vikings have two games left in their season....
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