ANSWER:-
THE ANSWER SHOULD BE PHENOL 
because due to symmetry in molecule there is only four signal in proton spectrum and also 4 signal in carbon spectrum and due to benzene proton chemical shift is in between 7-8 ppm. and one peak is in shielded region due to one -OH group.
and frequency of Ir spectra of OH group is in between 3100-3500 cm-1.
from mass spectroscopy mass of phenol or m/z = 94
arbitrary intensity Which of the following molecules produces the spectra above?
HAMA (NMR ΓΙ' arbitrary intensity ' το ΤΤΤΤΤΤΤΙΤΙ το ppm IMS αδιά Which of the following molecules produces the spectra above? (1 pt)
HNMR arbitrary intensity - 220 2200 200 160 160 180 120 100 200 5 Which of the following molecules produces the spectra above? (1 pt)
arbitrary intensity L200 220200100100 1201002 Which compound below gives the spectra above? ML Å w
3 of 8 arbitrary intensity Bogo Voz 6 ppm Which compound below gives the spectra above? uro in
HNMR --CNMR arbitrary intensity 200 100 100 100 120100 2 020 20 ppm MS Which compound below gives the spectra above? (1 pt)
please answer all parts of this question
Spectra of molecules in the microwave, infrared and ultraviolet regions of the electromagnetic spectrum have distinct differences. a. Sketch spectra in these three regions that show the above differences. 3. b. What physical change does the energy of a photon have on the molecules in these three regions. c. Discuss how the physical changes you mentioned in part b result in spectra in part a.
Please read the question carefully and answer all the parts. All
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