The answer is given as follows


help with these please N2(g) + O2(g) 2NO(g) Using the standard thermodynamic data in the tables...
AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 0 0 130.7 Hydrogen H2 (g) H (g) H' (g) H+ (aq) 218.0 203.2 114.7 1536.2 0 -230.0 -157.0 -11.0 -285.8 -237.1 69.9 OH(aq) H20 (1) H20 (g) H2O2 (1) -241.8 -228.6 188.8 -187.8 -120.4 109.6 Iodine AH.(kJ/mol). | AGO. (k.I/mol) go (I/mol K | -53.0 -13.0 242.0 -277.7 -174.8 160.7 282.7 -235.1 -484.0 160.0 C2H40 (g, ethylene oxide) CH3CH2OH (1) CH3CH2OH (g) CH3COOH (1) C2H6 (g) C3H6 (g) CzH; (g) CH2=CHCN (1)...
6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.92 moles of CO2(g) react at standard conditions. AGºrxn = Carbon AH°F (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 5.7 2.4 C(s, graphite) C(s, diamond) C(9) CC14 (1) 1.9 716.7 2.9 671.3 158.1 -135.4 -65.2 216.4 CCl4(9) -102.9 -60.6 309.9 CHCl3(1) -134.5 -73.7 201.7 CHCl3(9) -103.1 -70.3 295.7 CH4(9) -74.8 -50.7 186.3 CH3OH(g) -200.7 -162.0 239.8 CH3OH(1) -238.7 -166.3 126.8 H2CO(g) -116.0 219.0 HCOOH(g) -363.0...
Consider the reaction 2 CO2(g) +5 H2(e) C H2(e) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: Submit Answer Retry Entire Group more group attempts remaining AH,(kJ/mol) AG® (kJ/mol) Sº (J/mol K) -238.7 -116.0 126.8 219.0 -363.0 249.0 135.1 -166.3 -110.0 -351.0 125.0 209.2 68.2 - 129.0 202.0 226.7 200.9 52.3 - 166.0 -53.0 -277.7 219.6 250.0 242.0 160.7 -13.0 -235.1 282.7 Carbon CH3OH (1) H2CO...
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Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: N2(g) + O2(g) +2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: 2CO(g) + O2(g) +2002(9) - der e en manos de 20, ali ne more than one so mi dicogna undan Using standard thermodynamic data...
Consider the reaction: 12(g) + Cl2(g)—>21CI(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.950 moles of L2(g) react at standard conditions. AGºrxn = kJ Iodine AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 12(s) 0 0 116.1 12(9) 62.4 19.3 260.7 23.0 16.0 137 12(aq) I(g) 106.8 70.3 180.8 1 (9) -197.0 -55.0 -52.0 106.0 I'(aq) ICI(9) 17.8 -5.5 247.6 Chlorine Cl(9) AHºf (kJ/mol) AG°f (kJ/mol) sº (J/mol K) 121.7 105.7 165.2 0 0 223.1 -23.0...
Use standard thermodynamic data (in the Chemistry References) to calculate AG at 298.15 K for the following reaction, assuming that all gases have a pressure of 10.88 mm Hg. 2NO(g) + O2(g)—>2NO2(g) AG= kJ/mol Nitrogen AHºf (kJ/mol) AG°f (kJ/mol) sº (J/mol K) N2(g) 191.6 N(9) 472.7 455.6 153.3 NH3(9) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO(9) 90.3 86.6 210.8 NOCI(g) 51.7 66.1 261.8 NO2(9) 33.2 240.1 51.3 104.2 N2O(9) 82.1 219.9 N204(9) 9.2 97.9...
Nitrogen Ahºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 191.6 N2(9) 0 0 N(g) 472.7 455.6 153.3 NH3(g) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 90.3 86.6 210.8 NO(9) NOCI(g) 51.7 66.1 261.8 NO2(g) 33.2 51.3 240.1 N20(9) 82.1 104.2 219.9 N204(9) 9.2 97.9 304.3 N204(0) -20.0 97.0 209.0 N205(s) -42.0 134.0 178.0 N2H4(0) 50.6 149.3 121.2 N2H3CH3 () 54.0 180.0 166.0 HNO3(aq) -207.4 -111.3 146.4 HNO3(1) -174.1 -80.7 155.6 HNO3(9) -135.1 -74.7 266.4 NH4ClO4(s) -295.0...
(References TUTOR Entropy Change: Predict Sign, Calculate from Standard Entropy Values Consider the reaction CO(g) + H20(1)—CO2(g) + H2(g) Based upon the stoichiometry of the reaction the sign of AS rxn should be Using standard thermodynamic data, calculate AS rxn at 25°C. positive negative ASDXD J/K mol Submit Show Approach Show Tutor Steps Submit Answer Retry Entire Group 9 more group attempts remaining Selected Thermodynamic Data at 298.15 Kelvin Aluminum, Barium, Beryllium, Bromine, Cadmium, Calcium, Carbon, Chlorine, Chromium, Copper, Fluorine,...
Ethanol (C2H5OH) can be prepared by many different reactions including the two shown below: (2.1) C2H4 (g) + H20 (g) + C2H5OH (1) (2.2) C2H6 (g) + H20 (g) → C2H5OH (1) + H2 (g) Using the thermodynamic data below, calculate the change in the Gibbs free energy (in units of kJ) for reaction 2.1 at 298.15 K. AG; (kJ/mol) Sº (J/mol.K) 0 H2 (g) H2O (g) C2H5OH (1) C2H4 (g) -228.6 -174.9 68.0 AH; (kJ/mol) 0 -241.8 -277.7 52.5...
Consider the reaction: 2HBR(g) >H2(g) + Br2() Using standard thermodynamic data at 298K, calculate the free energy change when 1.51 moles of HBr(g) react at standard conditions AG° kJ rxn AHof (kJ/mol) AG°F (kJ/mol) s° (J/mol K) Beryllium Вe(s) 0 9.5 -569.0 ВeO(s) -599.0 14.0 Be(ОН)2(s) -902.5 -815.0 51.9 AH°f (kJ/mol) AG°f (kJ/mol) s° (J/mol K) Bromine Br(g) 111.9 175.0 82.4 Br2() 152.2 0 0 Br2(g) 30.9 3.1 245.5 Br2(aq) -3.0 4.0 130.0 -121.0 -175.0 82.0 Br (aq) BrF3(g) -255.6...