Question

Im having trouble figuring out how to do this question especially since "formed" is emphasized on. its the bottom one thats giving me trouble.

H-17 Practice Questions: Reaction Enthalpy Question 1: Neutralization Enthalpy Results (NaOH + HCI) Volume of NaOH (c = 1.25 mol L ) Volume of HCI (c = 1.00 moll) 6.9 un (use correct sign) Amount of limiting reagent (specify reagent) Astration per mole of water formed HCL CV-n mol kl mol 1. Calculate the heat of the reaction, re, in joules. Use the correct sign to indicate if heat is being absorbed or given off. Assume that the solution density is 1.00 g ml. Von d = 100g/mol 0 Stroncot çe4195/60g o mody t. - 2130 gren. - Cavcat) gren= -(loogima - 10000 m2 4.195mg 6.990) gryn. - 2891.15 or 1- 2.9 KT) exothermic to 28.04 B. Write the balanced molecular equation for the neutralization reaction of NaOH and HCI. Calculate Altrition (inkl mol-) per mole of water formed. & -2.745 Na Otting + HCling H₂O16) + No Cl cap)

Answer 1

penalne at = "Change in temperatung We know, them whene, AH = -mest L AH = Enthal Now, we know, .m = mass D Mass = Volume a density e = specific heat capacity total vol. of solution =(vol. of Nook tvol of Wel) = (50 +50) mi 100 me Now, Mass of the soln = 100ml alamil = 100g = 0.1 kg (as we know Y HOL 1 kg =10397 Now, specific heat capacity of wate=4.18 kg kg ik Here, temp. charge (At) = 6.9k

So, AH = - 0.184.18 x 6.9kT :. AH = -2.88 kJ (Exothermie) Now, the heat of the reaction is -2.88 kg Hene, heat u given off, neaction is exothermie. So, sign is (-Ue). B. Now, we know - lovo . Noon Hel Nael + H2O Now, volof. Nooh = 50ml. strength of Neuol = 1.25 molly So, no. of moles of Newl = 1.25 50 = 0.0625 Similarly, no oy moles of Hel - Távo 150 -0.05 Now, we know enthalpy change occurs When heutralisation son happens. Enthalpy change with the formation of 1 more of walim is Hieutralisation per mol of code B wille forma Heu. Hel with 0.05 mol is being the limiting reagent neacts with 0.05 mol of Nooth to produce 0.05 mol of H₂O. So, 0.05 mol of H2O = -2.88 ky heat. So, Aminut = 1 mol H20 femmelion - S =-57-6 kymai
If you still have any query feel free to ask in the comments and if you like my work please give a thumbs up.