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pH = 3.97
pH = -log [H+]
3.97 = -log [H+]
[H+] = 1.07*10^-4 M
CH3COOH dissociates as:
CH3COOH <-> CH3COO- + H+
Ka = [CH3COO-][H+] / [CH3COOH]
1.8*10^-5 = [CH3COO-] * (1.07*10^-4) / 0.031
[CH3COO-] = 5.21*10^-3 M
Answer: 5.21*10^-3 M
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