Question

4 10empts let Check my work Be sure to answer all parts. A0.4775 g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has m heat capacity of 3024 JeC. The temperature increases by 3.909°C. ts (a) Calculate the heat associated with the burning Mg in kJ/g kJ/g eBook (b) Calculate the heat associated with the burning of Mg in kJ/mol Pont kJ/mol eferences rew <Erex D Type here to search

Answer 1

Heat Capacity of Bomb Calorimeter = 3024 J/⁰C

$\Delta$T = 3.909⁰C

Heat Energy = Heat Capacity x $\Delta$T

$\Rightarrow$ Heat Energy = 3024 J/⁰C x 3.909⁰C = 11820.816 J = 11820.816 x 10^-3 kJ ~11.82 kJ [Since 1J = 10^-3 kJ]

This heat energy is released by 0.4775g of magnesium

$\Rightarrow$ Heat energy released by per gram of magnesium = 11.82 kJ / 0.4775g

$\Rightarrow$ Heat energy released by per gram of magnesium = 24.75 kJ/g

1 mol of magnesium weighs 24.30g

Heat energy released by per gram of magnesium = 24.75 kJ/g

Heat energy released by 24.30g of magnesium = 24.75 kJ/g x 24.30g

Heat energy released by 24.30g of magnesium = 601.4 kJ

$\Rightarrow$ Heat energy released by 1 mol of magnesium = 601.4 kJ [Since, 1 mol of magnesium weighs 24.30g]

Heat energy = 601.4 kJ/mol