4. At a given temperature Kgp of AgCl is 4.48 x 1010. Calculate the molar solubility...

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4. At a given temperature Kgp of AgCl is 4.48 x 1010. Calculate the molar solubility of AgCl at this temperature. 5.At a give

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Answer 1

Answer #1

Agu (6) & Agt (on) + c (4) Let is be the solubility (Agt] = 5= (u] Ksp = [ast] (u) = sxs=s? s 4.48x10-10 s= 2.11660105x105 m

Answer 2

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