(a)
Sample space, S is the set of all possible outcomes of choosing 4 options each for a question.
We have 4 questions. and so, n(S)=44 =256
(b)
A ={(1a,2a,3a,4a), (1a,2a,3a,4b), (1a,2a,3a,4c), (1a,2a,3a,4d), (1a,2a,4a,3b),(1a,2a,4a,3c),(1a,2a,4a,3d),(1a,3a,4a,2b),(1a,3a,4a,2c),(1a,3a,4a,2d),(2a,3a,4a,1b),(2a,3a,4a,1c),(2a,3a,4a,1d)}. So, n(A) =13
(c)
Pr(X=1) =Pr(Student passes) =number of favourable outcomes/total number of outcomes = n(A)/n(S).
n(S) =44 =256
n(A) =n(X=1) =4C3 *31 + 4C4 *30 =4(3)+1(1) =12+1 =13
Pr(X=1) =Pr(A) =13/256 =0.0508
l6 pts] Suppose that in the Province of Ontario the written cxam for a drivers license...
(3) (15 pts) Suppose that in the State of Nebraska the written exam for a drivers license consists of 4 multiple-choice questions. Each question has 4 possible choices, only one of which is correct. Passing requires answering at least 3 questions correctly. Consider an experiment: an uninformed student-driver guesses at random on each question, where "guessing at random" means that (i) the student answers each question independently of the other questions and (ii) that for each question the student chooses...
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