Question

The current in the RL circuit shown below reaches three-fifths its maximum value in 3.75 ms after the switch S, is thrown. 00

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Answer #1

a)

as we know from current equation

i = io e^( 1 - t/T)

1 - (3/5) io = io e^(- 3.75* 10^-3 / T)

T = 4.09 ms

=====

b)

T = L/R

R = 150* 10^-3/ (4.09* 10^-3) = 36.65 ohm

=====

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