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10 (15 pc) A jumper travels sliding down a track (He is not rotating). The jumper starts out (point A) from rest 40 above the
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Answer #1

Conserving energy we have

at point B

1/2 M V^2 = M*g*H g=9.8 m/s^2

Vb = sqrt(2*g*H) = 28 m/s no vertical component at B

at point C

Vc = sqrt(2*g*(H-25)) = 17.146 m/s

horizontal component = Vc*cos(37) = 13.17 m/s

vertical component = Vc*sin(37) = 10.287 m/s

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