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Given the following reactions

Question 1 Given the following reactions AH 66.4 k N2 (g)+202 (g)2NO2 (g) 2NO (g)+02 (g) 2NO2 (g) AH=-114.2 k the enthalpy of
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Answer #1

Reverse the equation (2 ho. - AH 14-2 kJ >2NOa) t 2NO2(0) 2 () Add equation &2 AH66.4 KJ 2NO (0) N2 a) t 2O2 ) 2NOg O2) 2NOL)

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