0.5 mL of 0.10 M Fe(NO3)3 is combined with 1 mL of 6 M HCl. Enter...

Question

Question

0.5 mL of 0.10 M Fe(NO₃)₃ is combined with 1 mL of 6 M HCl. Enter a balanced net ionic equation to illustrate the ligand substitution reaction.

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Answer 1

Answer #1

volume of re(NO3) = 0.5 ml = 1 Concentration of fe(nog), 0.10M = M, mnoles of re(NO3) =MU, = 0.10 x05=0.05 volume of Hill = 1

Answer 2

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