12. The value of AH° for the reaction below is.-336 kJ. Calculate the heat (kJ) released...

Question

Question

science chemistry

Answer 1

Answer #1

CH4 (g) + 30₂ (g) (H03 (d) + 3H (g) mole of HCl = 23.0g = 0.631 36.45 g/mol 0.63 DH = -336kJ SH/ mole HCl = -336 kJ/molile =0

Answer 2

Answer #2

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Answer 3

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