In 2012, A student earned a score of 163 on the vocabulary section of the GRE....
Homework Answers
here we are given that in 2012 , A student earned a score of 163 on the vocabulary section of the GRE.
the mean =150 and standard deviation =13.
p(x<163)=p(x-150/13<163-150/13)
=p(z<1)
=84.13%
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2012, A student earned a score of 163 on the vocabulary section of
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